====== 8. Lazy evaluation ====== When passing **parameters** to a function, programming language design offers **two options** which are not mutually exclusive (both strategies can be implemented in the language): * **applicative** (also called **strict**) evaluation strategy: * parameters are always evaluated **first** * can be further refined into: **call-by-value** (e.g. as it happens in C) and **call-by-reference** (e.g. as it happens for objects in Java). * **normal** evaluation strategy (also called **non-strict**, and when implemented as part of the PL - **call-by-name**) * the function is always evaluated **first** * can be further refined into: **lazy**, which ensures that each expression is evaluated **at most once** For more details, see the lecture on lazy evaluation. In Haskell, the default evaluation strategy is **lazy**. However, there are ways in which we can force evaluation to be **strict**. In this lab, we will explore several programming constructs which benefit from lazy evaluation. ===== 8.1. Streams ===== 8.1.1. Define the stream of natural numbers ''nat :: [Integer]''\\ 8.1.2. Define the stream of odd numbers. You can use other higher-order functions such as filter, map or zipWith.\\ 8.1.3. Define the stream of Fibonacci numbers ===== 8.2. Numerical approximations ===== 1. Define the ''build'' function which takes a generator ''g'' and an initial value ''a0'' and generates the infinite list: ''[a0, g a0, g (g a0), g (g (g a0)), .%%.%%. ]'' 2. Define the ''select'' function which takes a tolerance $math[e] and a list $math[l] and returns the element $math[l_n] which satisfies the following condition: $math[abs(l_n - l_{n+1}) < e] === Numerical Constants === == Phi == We know that $math[\displaystyle \lim_{n \rightarrow \infty} \frac{F_{n+1}}{F_n} = \varphi] (where $math[F_n] is the n-th element of the Fibonacci sequence, and $math[\varphi] is [[https://en.wikipedia.org/wiki/Golden_ratio|"the Golden Ratio"]]). More info [[https://en.wikipedia.org/wiki/Golden_ratio#Relationship_to_Fibonacci_sequence|here]]. 3. Write an approximation with ''0.001'' tolerance for the $math[\varphi] constant. Use the previously defined Fibonacci stream. == Pi == Consider the sequence: $math[a_{n+1} = a_n + sin(a_n)]; where $math[a_0] is an //initial approximation//, randomly chosen (but not 0 because $math[a_{n+1} != a_n]). We know that $math[\displaystyle \lim_{n \rightarrow \infty} a_n = \pi] 4. Write an approximation with ''0.001'' tolerance of the $math[\pi] constant. === Square Root === Given a number $math[k], we want to find a numerical approximation for $math[\sqrt{k}]. Consider the sequence: $math[a_{n+1} = \frac{1}{2}(a_n + \frac{k}{a_n})]; where $math[a_0] is an //initial approximation//, randomly chosen. We know that $math[\displaystyle \lim_{n \rightarrow \infty} a_n = \sqrt{k}]; more info [[https://en.wikipedia.org/wiki/Methods_of_computing_square_roots#Babylonian_method | here]]. 5. Write a function that approximates $math[\sqrt{k}] with ''0.001'' tolerance. === The Newton-Raphson Method === The sequence used for the approximation of the square root can be derived from the [[https://en.wikipedia.org/wiki/Newton%27s_method|Newton-Raphson method]], a generic method for finding the roots of a function (i.e. the points $math[x] for which $math[f(x) = 0]). Thus, for a function $math[f], we have the sequence: $math[x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}] We know that $math[\displaystyle \lim_{n \rightarrow \infty} x_n = r\ a.î.\ f(r) = 0]. 6. Write a function which takes a function and and its derivative and it approximates a root with ''0.001'' tolerance. === Derivatives === We can approximate the derivative of a function in a certain point using the definition of the derivative: $math[\displaystyle f'(a)=\lim_{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}] We can obtain better succesive approximations of the derivative in a point $math[a], using a smaller $math[h]. 7. Write a function which approximates the derivative of a function in a certain point. follow the steps: a) generate the sequence: $math[h_0, \frac{h_0}{2}, \frac{h_0}{4}, \frac{h_0}{8}, ...] (where $math[h_0] is a randomly chosen //initial approximation//)\\ b) generate the list of approximations for $math[f'(a)], using the formula above\\ c) write the function that takes a function $math[f] and a point $math[a] and approximates $math[f'(a)] with ''0.001'' tolerance, using the previous steps. === Integrals (: === Given a function $math[f], we can approximate the definite integral on $ [a, b]$, using the area of the trapezoid defined by $math[a, b, f(a), f(b)]: $math[\displaystyle \int_{a}^{b} f(x) dx \approx (b - a)\frac{f(a)+f(b)}{2}] We can obtain a better approximation by dividing the interval in two and adding the area of the two trapezoids defined by $math[a, m, f(a), f(m)] and $math[m, b, f(m), f(b)] (where $math[m] is the middle of the interval $ [a, b]$). We can obtain a better approximation by dividing these intervals in two and so on. 8. Write a function which approximates the integral of a function on an interval. Follow the steps: a) Write a function which takes a function $math[f] and two points $math[a, b] and calculates the area of the trapezoid $math[a, b, f(a), f(b)]\\ b) Write a function which takes a (ascending) list of points and inserts between any two points their middle: ''[1, 4, 7, 10, 13] -%%>%% [1, 2.5, 4, 5.5, 7, 8.5, 10, 11.5, 13]'' c) Write a function which takes a function $math[f] and a list of points $math[p_0,\ p_1,\ p_2,\ p_3,\ ...] and returns the list containing the areas of trapezoids defined by two consecutive points:\\ $math[(p_0, p_1, f(p_0), f(p_1));\ (p_1, p_2, f(p_1), f(p_2));\ (p_2, p_3, f(p_2), f(p_3));\ ...] d) Write a function which takes a function $math[f] and two points $math[a, b] and approximates $math[\displaystyle \int_{a}^{b} f(x) dx] with ''0.001'' tolerance, using the previous steps. ===== Recommended Reading ===== * [[http://worrydream.com/refs/Hughes-WhyFunctionalProgrammingMatters.pdf| Why Functional Programming Matters (especially section 4 "Gluing Programs Together", where the lab exercises are inspired from)]]