Differences
This shows you the differences between two versions of the page.
Both sides previous revision Previous revision Next revision | Previous revision | ||
lfa:reg [2018/07/23 13:37] pdmatei |
lfa:reg [2018/07/23 14:47] (current) pdmatei |
||
---|---|---|---|
Line 27: | Line 27: | ||
$justtheorem | $justtheorem | ||
- | Let $math[M] be a DFA. There exists a **regular expression** $math[E], such that $math[L(E)=L(A)]. | + | Let $math[M] be a DFA. There exists a **regular expression** $math[E], such that $math[L(E)=L(M)]. |
$end | $end | ||
Line 48: | Line 48: | ||
If $math[i = j], then: | If $math[i = j], then: | ||
- | * $math[R^{(0)}_{ii}] may contain **zero** transitions, hence $math[R^{(0)}_{ij} = \epsilon] | + | * $math[R^{(0)}_{ii}] may contain **zero** transitions, hence $math[R^{(0)}_{ij} = \epsilon] |
- | * $math[R^{(0)}_{ii}] may contain one transition, and the construction follows the above rules, yielding some regular expression $math[E_0]. | + | * $math[R^{(0)}_{ii}] may contain one transition, and the construction follows the above rules, yielding some regular expression $math[E_0]. |
We combine the two situations in a single one: $math[R^{(0)}_{ii} = \epsilon \cup E_0], where $math[E_0] is constructed as above. | We combine the two situations in a single one: $math[R^{(0)}_{ii} = \epsilon \cup E_0], where $math[E_0] is constructed as above. | ||