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lfa:2025:lab01 [2025/10/06 00:35] tpruteanu |
lfa:2025:lab01 [2025/10/07 12:02] (current) tpruteanu |
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- | **2.1.3.** The language of binary words which contain **exactly** two ones.yy | + | **2.1.3.** The language of binary words which contain **exactly** two ones. |
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**2.1.4.** (*) The language of words which encode binary numbers divisible by 3. | **2.1.4.** (*) The language of words which encode binary numbers divisible by 3. | ||
- | **2.1.5.** (* *) The language of words which encode binary numbers divisible by 3, represent in reverse order (the least significant digit is first). | + | **2.1.5.** (* *) The language of words which encode binary numbers divisible by 3, represented in reverse order (the least significant digit is first). |
**2.1.6.** (*) The language of quaternary words (base 4), that follow the rule that every zero is immediately followed by a sequence of at least 2 consecutive threes and every one is immediately followed by a sequence of at most 2 consecutive twos. | **2.1.6.** (*) The language of quaternary words (base 4), that follow the rule that every zero is immediately followed by a sequence of at least 2 consecutive threes and every one is immediately followed by a sequence of at most 2 consecutive twos. | ||
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iar dacă începe cu b. prima secvență este de al doilea tip */ | iar dacă începe cu b. prima secvență este de al doilea tip */ | ||
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**2.3.1** What happens if we switch all final states to non-final states and vice-versa in a DFA? | **2.3.1** What happens if we switch all final states to non-final states and vice-versa in a DFA? | ||
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**2.3.3** If no such cycle described above exist, L(M) is finite. | **2.3.3** If no such cycle described above exist, L(M) is finite. | ||
- | **2.3.4** Show that if you can construct a DFA to accept L, than you can also construct a DFA to accept $ L \cup \{a\}, a \in \Sigma $. | + | **2.3.4** Show that if you can construct a DFA to accept L, than you can also construct a DFA to accept $ L \cup \{a\}, \forall a \in \Sigma $. |