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====== Lab 03 - Turing Machines ======= | ====== Lab 03 - Turing Machines ======= | ||
+ | |||
+ | **Key concepts** | ||
+ | |||
+ | - acceptance vs decision | ||
+ | - complement of a problem | ||
+ | |||
+ | |||
+ | ==== 1. Accepting and deciding a decision problem ==== | ||
+ | |||
+ | **1.1** Can the problem $math[f(w) = 0] (for all w in $math[\Sigma^*]) be accepted by a Turing Machine? | ||
+ | |||
+ | **1.2** Can a problem be accepted by two different Turing Machines? | ||
+ | |||
+ | **1.3** Can a Turing Machine accept two different problems? | ||
+ | |||
+ | **1.4** Write a Turing Machine which accepts the problem $math[f(x) = 1] iff x (encoded as binary word) is odd, but does **NOT** decide it. | ||
+ | |||
+ | **1.5** Which of the following problems you think can be accepted and which can be decided? Use pseudocode instead of writing a TM. | ||
+ | |||
+ | **Diophantine equations (Hilbert's Tenth Problem)** | ||
+ | * A //diophantine// equation is a polynomial equation where only **integer solutions** are sought. | ||
+ | * Examples: | ||
+ | * $math[x^2+y^2=1] | ||
+ | * $math[x^4+y^4+z^4=w^4] | ||
+ | * $math[3x^2-2xy-y^2z-7=0] | ||
+ | * The decision problem we are interested in is: //Given a diophantine equation, does it have at least one solution//? | ||
+ | |||
+ | **Linear Integer Programming** | ||
+ | * You are given a set of arithmetic **constraints** over integers, and try to find if a solution to the constraints exists. | ||
+ | * Example: | ||
+ | * $math[y-x\leq 1] | ||
+ | * $math[3x+2y\leq 12] | ||
+ | * $math[2x+3y\leq 12] | ||
+ | |||
+ | **Wang Tiles** | ||
+ | * Wang tiles are squares where each **side** has a specific color. An example is given below. | ||
+ | {{ :aa:lab:wang_11_tiles.svg.png?200 |}} | ||
+ | * Wang tiles can be used to tile surfaces, but each tile must be placed such that adjacent tiles have the **same color side**. | ||
+ | * The wang tiling decision problem is: //Is it possible to tile the plane (an infinite surface) with a given set of tiles//? | ||
+ | |||
+ | **k-color** | ||
+ | * You are given a undirected graph and a number of ''k'' colors. Is it possible to assign a color to each node such that **no adjacent** (connected by an edge) nodes have the same color? | ||
+ | |||
+ | |||
+ | ==== 2. Complement ==== | ||
+ | |||
+ | **2.1** What is the complement of the problem from Exercise 1.1 ? | ||
+ | |||
+ | **2.2** What is the complement of k Vertex Cover? | ||
+ | |||
+ | **2.3** If a problem is decided by some TM, can its complement be decided? | ||
+ | |||
+ | **2.4** If a problem is accepted by some TM, can its complement be accepted? | ||
+ | |||
+ | ==== 3. Turing Machine pseudocode ==== | ||
+ | |||
+ | **3.1** Write a TM pseudocode which: | ||
+ | * takes a TM encoding enc(M) | ||
+ | * accepts if there exists a word which is accepted by M, in k steps | ||
+ | |||
+ | Suppose M is encoded on binary words, and also working on binary words, for simplicity. | ||
+ | |||
+ | /* Solution: | ||
+ | <code> | ||
+ | Pseudocode(M): <- input | ||
+ | - divide the tape on three sections: | ||
+ | - [word][value i][value k in binary][enc(M)] | ||
+ | - set the w=[word] section to "0", set the [value i] section to 0 in binary | ||
+ | - simulate w on M. After each transition, increment i and perform following checks | ||
+ | - if M accepts (crt state of M is final), go to final state | ||
+ | - if i == k: | ||
+ | "increment" the current word w. E.g. "0010" may be incremented as "0011" this is the "next" binary word | ||
+ | set i = 0 | ||
+ | repeat the same process all over | ||
+ | </code> | ||
+ | |||
+ | */ | ||
+ | |||
+ | **3.2** Which of the following pseudocode is a proper Turing Machine? Explain why. | ||
+ | |||
+ | <code> | ||
+ | Algoritm(M,w){ | ||
+ | if size(w) > 10 | ||
+ | then if M accepts w in k steps | ||
+ | accept. | ||
+ | } | ||
+ | </code> | ||
+ | |||
+ | <code> | ||
+ | Algoritm(M1,M2,w){ | ||
+ | k = 0 | ||
+ | while true | ||
+ | if M1 accepts w <=(iff)=> M2 accepts w , in k steps | ||
+ | then accept | ||
+ | else k = k + 1 | ||
+ | } | ||
+ | </code> | ||
+ | |||
+ | <code> | ||
+ | Algorithm(M,A) { | ||
+ | // A is a finite set of words | ||
+ | for each w in A | ||
+ | if M(w) accepts | ||
+ | then accept | ||
+ | } | ||
+ | </code> | ||
+ | |||
+ | <code> | ||
+ | Algorithm(M) { | ||
+ | if M accepts all words w in Sigma* | ||
+ | accept | ||
+ | } | ||
+ | </code> | ||
+ | |||
+ | <code> | ||
+ | Algorithm(M1,M2) { | ||
+ | if M1 always accepts then | ||
+ | if M2 always accepts then | ||
+ | accept | ||
+ | } | ||
+ | </code> | ||
+ | |||
+ | **3.4** Write a TM pseudocode which: | ||
+ | * takes two TMs as input | ||
+ | * accepts if there exists a word which is accepted by both TMs | ||
+ | |||
+ | **3.5** Write a TM pseudocode which: | ||
+ | * takes a word as input | ||
+ | * accepts if there exists a TM which accepts the word | ||
+ | |||
+ | **3.6** Write a TM pseudocode which: | ||
+ | * takes a Turing Machine M, and a finite set of words A | ||
+ | * checks if all words in A are accepted by M | ||
+ | |||
+ | **3.7** Write a TM pseudocode which: | ||
+ | * takes a Turing Machine M, and a finite set of words A | ||
+ | * checks if some words in A are accepted by M | ||