Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revision Previous revision
Next revision 		Previous revision
aa:lab:02 [2020/10/07 15:41]
pdmatei 		aa:lab:02 [2020/10/22 10:25] (current)
pdmatei
Line 1: Line 1:
-====== Lab 02 - Turing Machines =======+====== Lab 02 - Introduction to Turing Machines =======
  
 **Key concepts** **Key concepts**
Line 22: Line 22:
 ==== 1. A few basic Turing Machines ==== ==== 1. A few basic Turing Machines ====
  
-1.1 What does the following TM do? +**1.1** What does the following TM do? 
  
-$math[M=(K,​\Sigma,​q_0,​\delta,​F)] where $math[K=\{q_0,​q_1\}],​ $math[F=\{q_1\}], $math[\Sigma=\{0,​1,​\#​\}] and $math[\delta] is defined as below:+$math[M=(K,​\Sigma,​q_0,​\delta,​F)] where $math[K=\{q_0,​q_1,q_2\}], $math[F=\{q_2\}], $math[\Sigma=\{0,​1,​\#​\}] and $math[\delta] is defined as below:
  
-             ^ 0                ^ 1     ​^ #      ^ +^              ^ 0                ^ 1                ^ #                 ​^ 
-$math[q_0] ​  | $math[(q_0,​1,​R)] |       ​|        |+| $math[q_0] ​  | $math[(q_0,​1,​R)] | $math[(q_0,​0,​R)] ​| $math[(q_1,​0,​L)] ​ | 
 +| $math[q_1] ​  | $math[(q_1,​0,​L)] | $math[(q_1,​1,​L)] | $math[(q_2,​\#,​R)]  ​|
  
  
-  - (Answers online) What does the following TM do? (**bitwise complement**) +**1.2** Write a TM which **enters the final state** only if the **input** is a binary encoding of an **even** natural number. 
-  - (Answers online) ​Write a TM which **accepts** only if the **input** is a binary encoding of a **even** natural number. + 
-  - (Answers online) ​Write a TM which adds **5** to a number encoded in binary on the tape. The machine will always accept. +**1.3** Write a TM which verifies if a given word over alphabet $math[{A,​B}] contains the sequence ''​ABA''​. 
-  - (Answers online) Check if a symbol ​is present on the tape. + 
-  - (Discussion) ​How would the following algorithm be represented as a Turing Machine:+**1.4** ​Write a TM which adds **5** to a number encoded in binary on the tape.  
 + 
 +**1.5** Write a TM which checks ​if a binary number ''​x'' ​is strictly larger than ''​y''​. Hint: use a separator symbol between words. 
 + 
 +==== 2. Algorithms and Turing Machines ==== 
 + 
 +How would the following algorithm be represented as a Turing Machine:
 <​code>​ <​code>​
 Algorithm(vector V, integer M) { Algorithm(vector V, integer M) {
Line 40: Line 47:
    ​for-each x in V    ​for-each x in V
       s += x       s += x
-   if (x > 1000)+   if (s > M)
    ​then ​ return 1    ​then ​ return 1
    ​else ​ return 0    ​else ​ return 0
Line 50: Line 57:
   * how would ''​foreach x in V''​ be implemented?​   * how would ''​foreach x in V''​ be implemented?​
   * how would ''​s += x''​ be implemented?​   * how would ''​s += x''​ be implemented?​
-  * how would ''​if (x > 1000) then ... else ...''​ be implemented ?+  * how would ''​if (s > M) then ... else ...''​ be implemented ? 
 + 
 +/* 
 + 
 +**Answer:​** 
 +  * The input of the tape should contain each element of the vector ''​v'',​ encoded in binary, separated by a special character (e.g. ''​@''​). The last number in the sequence will be separated by another character (e.g. ''​!''​) from the value ''​M''​. 
 +  * The machine should accept if the algorithm returns 1, that is, if the sum of elements of the array is greater than ''​M''​ 
 +  * Before executing the foreach, the TM should //​allocate//​ part of its tape for the sum ''​s''​ which is initially 0. The LHS of the tape could be used. 
 +  * The foreach can be easily implemented by moving the cursor between ''​@''​ characters. 
 +  * For a particular ''​x'',​ we can implement binary adding between ''​x''​ and the current ''​s'':​ 
 +    * M should go back-and-forth between the location of ''​s''​ and that of the current ''​x''​. 
 +    * As each bit of ''​x''​ is processed, it should be erased (writing ''#''​) so that we can easily skip to the current ''​x''​. 
 +  * After ''​!''​ is read on the tape, we know we have finished the ''​foreach''​. We can then implement a bit-wise comparison of the values ''​s''​ and ''​M'',​ which would now be the current value of the tape. The machine accepts if ''​s > M''​.
  
-Homework:+*/ 
 +==== More practice exercises ====
   * Write a TM which verifies if a string has the **same number** of ones and zeroes. Give hints - live (what should the machine do?)   * Write a TM which verifies if a string has the **same number** of ones and zeroes. Give hints - live (what should the machine do?)
   * write a TM which **accepts** a given regular expression   * write a TM which **accepts** a given regular expression
   * write a TM which **reverses** a given binary string (always accepts)   * write a TM which **reverses** a given binary string (always accepts)